Diskussion:Repetera konjugatregeln: Skillnad mellan sidversioner
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Rad 2: | Rad 2: | ||
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1. (1+x)(1-x) = | 1. (1+x)(1-x) = 1-x<sup>2</sup> | ||
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2. (2+2x)(2-2x) = | 2. (2+2x)(2-2x) = 4-4x<sup>2</sup> | ||
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3. (2+3x)(2-3x) = | 3. (2+3x)(2-3x) = 4-9<sup>2</sup> | ||
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4. (10+11x)(10-11x) = | 4. (10+11x)(10-11x) = 100-121x<sup>2</sup> | ||
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5. (0.1+10x)(0.1-10x) = | 5. (0.1+10x)(0.1-10x) =0.01-100x<sup>2</sup> | ||
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6. (a+b)(a-b) = | 6. (a+b)(a-b) = a<sup>2</sup> -b<sup>2</sup> | ||
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7. (a+bx)(a-bx) = | 7. (a+bx)(a-bx) = a<sup>2</sup> -b<sup>2</sup> x<sup>2</sup> | ||
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8. (0.5a+3x)(0.5a-3x) = | 8. (0.5a+3x)(0.5a-3x) = 0-25a<sup>2</sup> -9x<sup>2</sup> | ||
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9. (3y+2x<sup>2</sup>)(3y-2x<sup>2</sup>) = | 9. (3y+2x<sup>2</sup>)(3y-2x<sup>2</sup>) = 9y<sup>2</sup> -4x<sup>2</sup> | ||
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Versionen från 6 februari 2012 kl. 12.28
Använd konjugatregeln för att ta bort parenteserna i följande uttryck:
1. (1+x)(1-x) = 1-x2
2. (2+2x)(2-2x) = 4-4x2
3. (2+3x)(2-3x) = 4-92
4. (10+11x)(10-11x) = 100-121x2
5. (0.1+10x)(0.1-10x) =0.01-100x2
6. (a+b)(a-b) = a2 -b2
7. (a+bx)(a-bx) = a2 -b2 x2
8. (0.5a+3x)(0.5a-3x) = 0-25a2 -9x2
9. (3y+2x2)(3y-2x2) = 9y2 -4x2